Example
\( f(x) = \sqrt{x} \) Domain: \( [0, \infty) \)
\[ f'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h} \]
\[ = \lim_{h \to 0} \frac{\sqrt{x + h} - \sqrt{x}}{h} \cdot \frac{\sqrt{x + h} + \sqrt{x}}{\sqrt{x + h} + \sqrt{x}} \quad \text{rationalize} \]
\[ = \lim_{h \to 0} \frac{(\sqrt{x + h})^2 - (\sqrt{x})^2}{h(\sqrt{x + h} + \sqrt{x})} = \lim_{h \to 0} \frac{x + h - x}{h(\sqrt{x + h} + \sqrt{x})} \]
\[ = \lim_{h \to 0} \frac{h}{h(\sqrt{x + h} + \sqrt{x})} = \lim_{h \to 0} \frac{1}{\sqrt{x + h} + \sqrt{x}} = \frac{1}{\sqrt{x} + \sqrt{x}} = \frac{1}{2\sqrt{x}} \]
Figure: Graph of y equals square root of x, showing the curve and a tangent line at a point.
Slope = \( \frac{1}{2\sqrt{x}} \)
\( y = \sqrt{x} \)
Note \( f'(x) \) has domain \( (0, \infty) \)
Not same as \( f(x) \)
\( f'(0) \) DNE
\( f(x) \) is not differentiable at 0