1.2 Row Reduction and Echelon Forms
\(-3R_1 + R_2\)
\(-5R_1 + R_3\)
\(-2R_2 + R_3\)
this is now in Row Echelon Form
ladders / stairs
\(-3R_1 + R_2\)
\(-5R_1 + R_3\)
\(-2R_2 + R_3\)
this is now in Row Echelon Form
ladders / stairs
let's go further and make more entries zeros
\(-3R_2 + R_1\)
\(-3R_3 + R_2\)
\(2R_3 + R_1\)
this is now in Reduced Row Echelon Form
this matrix is in reduced row echelon form because (must satisfy conditions 1-3 above)
the reduced row echelon form of a matrix is unique
neither because zero row not at bottom
row echelon
reduced row echelon
back to
in reduced row echelon form
the locations of the leading 1's are called pivot positions
the columns containing leading 1's are pivot columns
original matrix:
the elements correspond to the pivot positions in reduced echelon form are the ones used to make other rows in their column zeros
The row reduction algorithm can be done to ANY matrix, not just augmented matrix of system.
In a system, the number of pivots (not in last column) corresponds to the number of basic variables in a system.
row equivalent to
sys has 3 variables, 1 pivot (corresponds to \(x_1\))
\(\Rightarrow x_2\) and \(x_3\) are free variables
\(x_1\) (pivot column) is a basic variable
# of zero rows = # of free variables
The augmented matrix of some system reduces to:
3 variables, 3 pivots. One solution: \( (1, -1, 1) \)
The augmented matrix of some system reduces to:
"overdetermined system"
more eqs. than variables
3 variables, 3 pivots BUT one in right most column.
Row 3 \( \rightarrow 0 = 1 \)
no solution (inconsistent system)
Even though there is a zero row, system is inconsistent, no solution.
Any time there is a pivot in the right most column of the reduced echelon form of an augmented matrix of a system \( \Rightarrow \) inconsistent system, no solution.