9.1 (continued)
If \( f(x) \) is periodic w/ period of \( 2\pi \) defined on \( -\pi < x < \pi \), then its Fourier series representation is
where
Last time:
period \( 2\pi \)
If \( f(x) \) is periodic w/ period of \( 2\pi \) defined on \( -\pi < x < \pi \), then its Fourier series representation is
where
period \( 2\pi \)
We had:
So, its Fourier series representation is
Just like Taylor series, the more terms we include the better the Fourier series resembles the true \( f(x) \).
Let's look at the function defined by:
The function has a period of \(2\pi\).
The Fourier coefficient \(a_n\) is given by:
We calculate the first coefficient by finding the area under the curve:
Using integration by parts:
After performing the integration:
Calculating the sine coefficients using integration by parts:
The resulting Fourier series for \( f(x) \) is:
Expanding the first few terms of the series:
Try this one: \( f(x) = |x| \) for \( -\pi < x < \pi \) with period \( 2\pi \).
The piecewise definition of the function over one period is:
The constant coefficient \( a_0 \) is calculated as the average value over the period:
The cosine coefficients \( a_n \) are found to be:
The sine coefficients \( b_n \) are zero because the function is even: