Sturm-Liouville Theory
1-D Heat eq:
\( u_t = k u_{xx} \)
\( 0 < x < L \)
we've seen that if \( u(0, t) = u(L, t) = 0 \) (ends frozen)
then \( \lambda_n = \frac{n^2 \pi^2}{L^2} \)
with \( X_n = \sin(\sqrt{\lambda} x) = \sin\left(\frac{n\pi}{L}x\right) \)
\( n = 1, 2, 3, \dots \)
if \( u_x(0, t) = u_x(L, t) = 0 \) (ends insulated)
then \( \lambda_n = \frac{n^2 \pi^2}{L^2} \)
with \( X_n = \cos(\sqrt{\lambda} x) = \cos\left(\frac{n\pi}{L}x\right) \)
\( n = 0, 1, 2, 3, \dots \)
in both cases, the eigenvalues \( \lambda_n \) give us the frequencies of the modes of solutions \( \rightarrow \) all integer multiples of \( \frac{\pi}{L} \)
and the eigenfunctions are all mutually orthogonal