MA 161 Fall 2026 – Lesson 1 (08/24/26)
Today:
- Syllabus discussion
- Introduction to the course
- Review of functions
Announcements:
- READ THE SYLLABUS
- Get aquainted with course schedule
- Enroll in MyLab Math HW System
Office Hours: MWF 1:30 PM – 2:30 PM
Today:
Announcements:
Office Hours: MWF 1:30 PM – 2:30 PM
Rule that assigns an output to each input
\[ \underset{\substack{\uparrow \\ \text{output}}}{y} = f(\underset{\substack{\uparrow \\ \text{input}}}{x}) \]
eg: \( y = f(x) = x^3 - 5x + 1 \)
\(\text{input} = 0 \rightsquigarrow \text{Output} = 0^3 - 5 \cdot 0 + 1 = 1\)
\(\text{input} = 1 \rightsquigarrow \text{Output} = 1^3 - 5 \cdot 1 + 1 = -3\)
\(\text{input} = k \rightsquigarrow \text{Output} = k^3 - 5k + 1\)
on a graph w input on Horizontal Axis
Ouput on vertical Axis
Graph of function
Not a graph of function.
Domain: all acceptable inputs
Range: All possible outputs
eg: \( f(x) = \sqrt{x+5} \)
Domain: \( [-5, \infty) \)
Range: \( [0, \infty) \)
eg: Find domain of \( f(x) = \sqrt{x-1} - \frac{1}{\sqrt{2-x}} \)
\( \sqrt{x-1} \rightarrow \) acceptable input is \( x \ge 1 \)
\( \sqrt{2-x} \rightarrow \) acceptable input is \( 2-x \ge 0 \) or \( x \le 2 \)
Want both \( \Rightarrow \) Domain is \( x \ge 1 \) and \( x \le 2 \)
\( [1, 2] \)
Not really \( \rightarrow \) Cannot have \( \sqrt{2-x} = 0 \Rightarrow x \neq 2 \)
\( \text{Domain} = [1, 2) \)
\[ h(x) = f(x) + c \rightsquigarrow \text{up by } c \text{ units} \]
\[ h(x) = f(x) - c \rightsquigarrow \text{down by } c \text{ units} \]
\[ g(x) = f(x - k) \rightsquigarrow \text{Right by } k \text{ units} \]
\[ g(x) = f(x + k) \rightsquigarrow \text{Left by } k \text{ units} \]
\[ h(x) = c \, f(x) \]
\[ c > 1 \implies \text{stretching} \]
\[ 0 < c < 1 \implies \text{compressing} \]
\[ g(x) = f(cx) \quad \text{or} \quad f\left(\frac{x}{c}\right) \]
For \( f(cx) \):
For \( f\left(\frac{x}{c}\right) \):
\( g(x) = f(-x) \) is reflection about y-axis
\( h(x) = -f(x) \) is reflection about x-axis.