Coverage: Lessons 17–33  (§15.8, §16.1–16.6, §17.1–17.6)

Exam Date: Tuesday, April 21, 2026

Time: 8:00 PM - 9:00 PM

Location: Announced on Brightspace

Lagrange Multipliers [Lesson 17] (§15.8)

Method of Lagrange Multipliers

To find the extreme values of \(f(x,y)\) subject to a constraint \(g(x,y) = k\), solve the system:

\[\nabla f = \lambda\,\nabla g \qquad \text{and} \qquad g(x,y) = k\]

That is:

Three Variables

To optimize \(f(x,y,z)\) subject to \(g(x,y,z) = k\):

\[\nabla f = \lambda\,\nabla g \qquad \text{and} \qquad g(x,y,z) = k\]

Note: Evaluate \(f\) at all solution points and compare to identify absolute max/min.

Practice Problems

Double Integrals over Rectangular Regions [Lesson 18] (§16.1)

Double Integral over a Rectangle

For \(R = [a,b] \times [c,d]\):

\[\iint_R f(x,y)\,dA = \int_a^b \int_c^d f(x,y)\,dy\,dx = \int_c^d \int_a^b f(x,y)\,dx\,dy\]

Fubini's Theorem

If \(f\) is continuous on \(R = [a,b]\times[c,d]\), the order of integration may be switched:

\[\int_a^b\int_c^d f(x,y)\,dy\,dx = \int_c^d\int_a^b f(x,y)\,dx\,dy\]

Riemann Sum Definition

Partition \([a,b]\) into \(m\) subintervals and \([c,d]\) into \(n\) subintervals, each of width \(\Delta x = \frac{b-a}{m}\) and \(\Delta y = \frac{d-c}{n}\). Choose sample points \((x_{ij}^*, y_{ij}^*)\) in each subrectangle \(R_{ij}\):

\[\iint_R f(x,y)\,dA = \lim_{m,n\to\infty}\sum_{i=1}^{m}\sum_{j=1}^{n} f(x_{ij}^*,\, y_{ij}^*)\,\Delta A\]

where \(\Delta A = \Delta x\,\Delta y\) is the area of each subrectangle.

Practice Problems

Double Integrals over General Regions [Lesson 19] (§16.2)

Type I Region (vertical strips)

Region bounded by functions of \(x\): \(g_1(x) \le y \le g_2(x)\), \(a \le x \le b\)

\[\iint_D f(x,y)\,dA = \int_a^b\int_{g_1(x)}^{g_2(x)} f(x,y)\,dy\,dx\]

Type II Region (horizontal strips)

Region bounded by functions of \(y\): \(h_1(y) \le x \le h_2(y)\), \(c \le y \le d\)

\[\iint_D f(x,y)\,dA = \int_c^d\int_{h_1(y)}^{h_2(y)} f(x,y)\,dx\,dy\]

Reversing Order of Integration

Sketch the region, identify bounds for the opposite order, then re-write the integral. This is often necessary when the inner integral has no elementary antiderivative.

Practice Problems

Double Integrals in Polar Coordinates [Lesson 20] (§16.3)

Polar Coordinate Substitution

Use \(x = r\cos\theta\), \(y = r\sin\theta\), \(x^2+y^2=r^2\):

\[\iint_D f(x,y)\,dA = \int_\alpha^\beta\int_{r_1(\theta)}^{r_2(\theta)} f(r\cos\theta,\, r\sin\theta)\,r\,dr\,d\theta\]

Key: Don't forget the Jacobian factor \(r\) in \(dA = r\,dr\,d\theta\).

When to Use Polar Coordinates

Practice Problems

Triple Integrals [Lesson 21] (§16.4)

Iterated Triple Integral

\[\iiint_E f(x,y,z)\,dV = \int_a^b\int_{g_1(x)}^{g_2(x)}\int_{u_1(x,y)}^{u_2(x,y)} f(x,y,z)\,dz\,dy\,dx\]

Applications

Note: There are 6 possible orders of integration — choose the order that fits the region and integrand most naturally.

Practice Problems

Triple Integrals in Cylindrical Coordinates [Lesson 22] (§16.5)

Cylindrical Coordinates

Relation to rectangular coordinates:

\[x = r\cos\theta,\quad y = r\sin\theta,\quad z = z\] \[r^2 = x^2+y^2,\quad \tan\theta = \frac{y}{x}\]

Triple Integral in Cylindrical Coordinates

\[\iiint_E f(x,y,z)\,dV = \int_\alpha^\beta\int_{r_1}^{r_2}\int_{u_1}^{u_2} f(r\cos\theta,r\sin\theta,z)\,r\,dz\,dr\,d\theta\]

Key: Don't forget the Jacobian factor \(r\) in \(dV = r\,dz\,dr\,d\theta\).

When to Use Cylindrical Coordinates

Practice Problems

Triple Integrals in Spherical Coordinates [Lesson 23] (§16.5)

Spherical Coordinates

\[x = \rho\sin\phi\cos\theta,\quad y = \rho\sin\phi\sin\theta,\quad z = \rho\cos\phi\] \[\rho^2 = x^2+y^2+z^2, \quad \rho \ge 0,\quad 0 \le \phi \le \pi,\quad 0 \le \theta \le 2\pi\]

Triple Integral in Spherical Coordinates

\[\iiint_E f\,dV = \int_0^{2\pi}\int_0^{\phi_{\max}}\int_0^{\rho_{\max}} f\,\rho^2\sin\phi\,d\rho\,d\phi\,d\theta\]

Key: The Jacobian is \(\rho^2\sin\phi\). Don't forget it!

Useful Identities

Practice Problems

Integrals in Mass Calculations [Lesson 24] (§16.6)

Mass, Moments, and Center of Mass

For a lamina (2D) with density \(\delta(x,y)\):

\[m = \iint_D \delta(x,y)\,dA\] \[\bar{x} = \frac{1}{m}\iint_D x\,\delta(x,y)\,dA, \qquad \bar{y} = \frac{1}{m}\iint_D y\,\delta(x,y)\,dA\]

3D Solid

For a solid \(E\) with density \(\delta(x,y,z)\):

\[m = \iiint_E \delta(x,y,z)\,dV\] \[\bar{x} = \frac{1}{m}\iiint_E x\,\delta\,dV,\quad \bar{y} = \frac{1}{m}\iiint_E y\,\delta\,dV,\quad \bar{z} = \frac{1}{m}\iiint_E z\,\delta\,dV\]

Moments of Inertia

\[I_x = \iint_D y^2\,\delta\,dA,\quad I_y = \iint_D x^2\,\delta\,dA,\quad I_0 = \iint_D (x^2+y^2)\,\delta\,dA\]

Practice Problems

Vector Fields [Lesson 25] (§17.1)

Definition

A vector field assigns a vector to each point in a region:

\[\vec{F}(x,y) = P(x,y)\,\vec{i} + Q(x,y)\,\vec{j} = \langle P, Q \rangle\] \[\vec{F}(x,y,z) = P\,\vec{i} + Q\,\vec{j} + R\,\vec{k} = \langle P, Q, R \rangle\]

Conservative Vector Fields

A vector field \(\vec{F}\) is conservative if there exists a scalar function \(f\) (the potential function) such that:

\[\vec{F} = \nabla f \qquad \Longleftrightarrow \qquad P = f_x,\; Q = f_y \; (\text{and }R = f_z)\]

Test for Conservative Field in 2D

\[\vec{F} = \langle P, Q \rangle \text{ is conservative} \iff \frac{\partial P}{\partial y} = \frac{\partial Q}{\partial x}\]

Practice Problems

Line Integrals of Functions [Lesson 26] (§17.2)

Line Integral of a Scalar Function

For curve \(C\) parametrized by \(\vec{r}(t)\), \(a \le t \le b\):

\[\int_C f(x,y,z)\,ds = \int_a^b f(\vec{r}(t))\,|\vec{r}'(t)|\,dt\]

Interpretations

Practice Problems

Line Integrals of Vector Fields [Lesson 27] (§17.2)

Line Integral of a Vector Field (Work)

The work done by \(\vec{F}\) along curve \(C\):

\[\int_C \vec{F}\cdot d\vec{r} = \int_a^b \vec{F}(\vec{r}(t))\cdot\vec{r}'(t)\,dt = \int_C P\,dx + Q\,dy + R\,dz\]

Key Properties

Practice Problems

Fundamental Theorem of Line Integrals [Lesson 28] (§17.3)

Fundamental Theorem of Line Integrals

If \(\vec{F} = \nabla f\) (conservative) and \(C\) goes from \(A\) to \(B\):

\[\int_C \nabla f \cdot d\vec{r} = f(B) - f(A)\]

Independence of Path

\(\displaystyle\int_C \vec{F}\cdot d\vec{r}\) is path-independent if and only if \(\vec{F}\) is conservative.

Closed Curves

\[\oint_C \vec{F}\cdot d\vec{r} = 0 \iff \vec{F} \text{ is conservative}\]

Finding the Potential Function

Given \(\vec{F} = \langle P, Q \rangle\) is conservative:

Practice Problems

Green's Theorem [Lesson 29] (§17.4)

Green's Theorem

Let \(C\) be a positively oriented (counterclockwise), simple closed curve bounding region \(D\):

\[\oint_C P\,dx + Q\,dy = \iint_D \left(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}\right)dA\]

Area via Green's Theorem

\[A = \oint_C x\,dy = -\oint_C y\,dx = \frac{1}{2}\oint_C x\,dy - y\,dx\]

Note: Green's theorem converts a difficult line integral into a double integral, or vice versa.

Practice Problems

Curl and Divergence [Lesson 30] (§17.5)

Curl

For \(\vec{F} = \langle P, Q, R \rangle\):

\[\text{curl}\,\vec{F} = \nabla \times \vec{F} = \begin{vmatrix}\vec{i} & \vec{j} & \vec{k} \\ \partial_x & \partial_y & \partial_z \\ P & Q & R\end{vmatrix} = \left\langle R_y - Q_z,\, P_z - R_x,\, Q_x - P_y \right\rangle\]

Divergence

\[\text{div}\,\vec{F} = \nabla \cdot \vec{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z}\]

Key Identities

Practice Problems

Surface Integrals [Lessons 31–33] (§17.6)

Surface Integral of a Scalar Function

For surface \(z = g(x,y)\) over region \(D\):

\[\iint_S f(x,y,z)\,dS = \iint_D f(x,y,g(x,y))\sqrt{g_x^2 + g_y^2 + 1}\,dA\]

Surface Area

\[A(S) = \iint_S dS = \iint_D \sqrt{g_x^2 + g_y^2 + 1}\,dA\]

Flux Integral (Surface Integral of a Vector Field)

For \(\vec{F} = \langle P, Q, R \rangle\) and oriented surface \(S\) with unit normal \(\hat{n}\):

\[\iint_S \vec{F}\cdot d\vec{S} = \iint_S \vec{F}\cdot\hat{n}\,dS\]

For \(z = g(x,y)\) with upward orientation (\(\hat{n}\) pointing upward):

\[\iint_S \vec{F}\cdot d\vec{S} = \iint_D \left(-P g_x - Q g_y + R\right)dA\]

Parametric Surface

For surface \(\vec{r}(u,v)\):

\[\iint_S f\,dS = \iint_D f(\vec{r}(u,v))\,|\vec{r}_u \times \vec{r}_v|\,dA\]
\[\iint_S \vec{F}\cdot d\vec{S} = \iint_D \vec{F}(\vec{r}(u,v))\cdot(\vec{r}_u \times \vec{r}_v)\,dA\]

Practice Problems