Solving \( m \times n \) Linear System
\( m \times n \) linear system: (\( m \) equations in \( n \) unknowns)
\[ \begin{cases} a_{11} x_1 + a_{12} x_2 + \cdots + a_{1n} x_n = b_1 \\ a_{21} x_1 + a_{22} x_2 + \cdots + a_{2n} x_n = b_2 \\ \vdots \qquad \vdots \qquad\qquad \vdots \\ a_{m1} x_1 + a_{m2} x_2 + \cdots + a_{mn} x_n = b_m \end{cases} \]\( \Updownarrow \) In matrix notation: \( A\vec{X} = \vec{B} \)
\[ \begin{bmatrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & & & \\ a_{m1} & a_{m2} & \cdots & a_{mn} \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \\ \vdots \\ x_n \end{bmatrix} = \begin{bmatrix} b_1 \\ b_2 \\ \vdots \\ b_m \end{bmatrix} \]\( \Updownarrow \) In terms of linear combination: (columns of \( A \))
\[ x_1 \begin{bmatrix} a_{11} \\ a_{21} \\ a_{31} \\ \vdots \\ a_{m1} \end{bmatrix} + x_2 \begin{bmatrix} a_{12} \\ a_{22} \\ a_{32} \\ \vdots \\ a_{m2} \end{bmatrix} + \cdots + x_n \begin{bmatrix} a_{1n} \\ a_{2n} \\ \vdots \\ a_{mn} \end{bmatrix} = \begin{bmatrix} b_1 \\ b_2 \\ \vdots \\ b_m \end{bmatrix} \]For linear system, one and only one of the following cases can occur:
- there is a unique (ie. only one) solution;
- there are infinitely many solutions;
- there is no solution.
In the case of \( 2 \times 2 \) linear system, the above 3 cases correspond to:
(1)
Figure 1
(2)
Figure 2
(3)
Figure 3
Ex1
\[ \begin{cases} 2x + y = -1 \\ x - 3y = 5 \end{cases} \] \[ \left[\begin{array}{cc|c} 2 & 1 & -1 \\ 1 & -3 & 5 \end{array}\right] \rightarrow \left[\begin{array}{cc|c} 1 & -3 & 5 \\ 2 & 1 & -1 \end{array}\right] \rightarrow \left[\begin{array}{cc|c} 1 & -3 & 5 \\ 0 & 7 & -11 \end{array}\right] \]\( 7y = -11 \Rightarrow y = -\frac{11}{7} \)
\( x - 3y = 5 \)
\[ \begin{gathered} x = 5 + 3y = 5 - \frac{33}{7} = \frac{2}{7} \\[0.5em] \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} \frac{2}{7} \\ -\frac{11}{7} \end{pmatrix} \end{gathered} \]Figure 4
2 lines intersect at a unique point.
Ex2
\[ \begin{cases} x + 2y + z = 1 \\ 3x + y + 4z = 0 \\ 2x + 2y + 3z = 2 \end{cases} \] \[ \left[\begin{array}{ccc|c} 1 & 2 & 1 & 1 \\ 3 & 1 & 4 & 0 \\ 2 & 2 & 3 & 2 \end{array}\right] \rightarrow \left[\begin{array}{ccc|c} 1 & 2 & 1 & 1 \\ 0 & -5 & 1 & -3 \\ 0 & -2 & 1 & 0 \end{array}\right] \] \[ \rightarrow \left[\begin{array}{ccc|c} 1 & 2 & 1 & 1 \\ 0 & 1 & -\frac{1}{5} & \frac{3}{5} \\ 0 & 1 & -\frac{1}{2} & 0 \end{array}\right] \rightarrow \left[\begin{array}{ccc|c} 1 & 2 & 1 & 1 \\ 0 & 1 & -\frac{1}{5} & \frac{3}{5} \\ 0 & 0 & -\frac{3}{10} & -\frac{3}{5} \end{array}\right] \]\( z = 2 \)
\( y = \frac{3}{5} + \frac{z}{5} = 1 \)
\( x = 1 - 2y - z = 1 - 2 - 2 = -3 \)
\[ \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} -3 \\ 1 \\ 2 \end{pmatrix} \]Figure 5
3 planes intersect at a point.
Ex3
\( x - 6y = 7 \) \(\longleftarrow\) a line
\( y = s \) (free), \( x = 7 + 6s \)
\[ \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} 7 + 6s \\ s \end{pmatrix} = \begin{pmatrix} 7 \\ 0 \end{pmatrix} + s \begin{pmatrix} 6 \\ 1 \end{pmatrix} \]parametric form shift direction of line
Figure 6
Ex4
\[ \begin{cases} x + 3y = -1 \\ 4x + 12y = -4 \end{cases} \]2 same lines
\[ \left[\begin{array}{cc|c} 1 & 3 & -1 \\ 4 & 12 & -4 \end{array}\right] \rightarrow \left[\begin{array}{cc|c} 1 & 3 & -1 \\ 0 & 0 & 0 \end{array}\right] \]\( y = s \) (free)
(pivot) \( x = -1 - 3y = -1 - 3s \)
\[ \begin{pmatrix} x \\ y \end{pmatrix} = \begin{pmatrix} -1 - 3s \\ s \end{pmatrix} = \begin{pmatrix} -1 \\ 0 \end{pmatrix} + s \begin{pmatrix} 3 \\ 1 \end{pmatrix} \]parametric form shift direction
Figure 7
2 same lines
Ex5
\[ \begin{cases} x + 3y = -1 \\ 2x + 6y = 3 \end{cases} \] \[ \left[\begin{array}{cc|c} 1 & 3 & -1 \\ 2 & 6 & 3 \end{array}\right] \rightarrow \left[\begin{array}{cc|c} 1 & 3 & -1 \\ 0 & 0 & 5 \end{array}\right] \]no solution
\( 0y = 5 \)
Figure 8
2 unequal parallel lines, no intersection
Ex6
\[ \begin{cases} x + 3y - z = 5 \\ 2x - y + z = 10 \end{cases} \] \[ \left(\begin{array}{ccc|c} 1 & 3 & -1 & 5 \\ 2 & -1 & 1 & 10 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & 3 & -1 & 5 \\ 0 & -7 & 3 & 0 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & 3 & -1 & 5 \\ 0 & 1 & -\frac{3}{7} & 0 \end{array}\right) \]\( z = \alpha \) (free)
\( y = \frac{3}{7} z = \frac{3}{7} \alpha \)
\( x = 5 - 3y + z = 5 - \frac{9}{7}\alpha + \alpha = 5 - \frac{2}{7}\alpha \)
\[ \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} 5 - \frac{2}{7}\alpha \\ \frac{3}{7}\alpha \\ \alpha \end{pmatrix} = \begin{pmatrix} 5 \\ 0 \\ 0 \end{pmatrix} + \alpha \begin{pmatrix} -\frac{2}{7} \\ \frac{3}{7} \\ 1 \end{pmatrix} \]parametric form shift direction of line
Figure 9
Ex7
\[ \begin{cases} x - y + 2z = 7 \\ 2x - 2y + 4z = 14 \end{cases} \] \[ \left(\begin{array}{ccc|c} 1 & -1 & 2 & 7 \\ 2 & -2 & 4 & 14 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & -1 & 2 & 7 \\ 0 & 0 & 0 & 0 \end{array}\right) \]\( z = \alpha \) (free)
\( y = \beta \) (free)
\( x = \beta - 2\alpha + 7 \)
\[ \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} 7 + \beta - 2\alpha \\ \beta \\ \alpha \end{pmatrix} = \begin{pmatrix} 7 \\ 0 \\ 0 \end{pmatrix} + \beta \begin{pmatrix} 1 \\ 1 \\ 0 \end{pmatrix} + \alpha \begin{pmatrix} -2 \\ 0 \\ 1 \end{pmatrix} \]Figure 10
2 planes the same
Ex8
\[ \begin{cases} x - y + 2z = 7 \\ 3x - 3y + 6z = 2 \end{cases} \] \[ \left(\begin{array}{ccc|c} 1 & -1 & 2 & 7 \\ 3 & -3 & 6 & 2 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & -1 & 2 & 7 \\ 0 & 0 & 0 & -19 \end{array}\right) \]no solution
Figure 11
2 unequal, parallel planes, no intersection
Ex9
\[ \begin{cases} x + y - z = 2 \\ 3x - y + 2z = 0 \\ 2x - 2y + 3z = -2 \end{cases} \] \[ \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 3 & -1 & 2 & 0 \\ 2 & -2 & 3 & -2 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 0 & -4 & 5 & -6 \\ 0 & -4 & 5 & -6 \end{array}\right) \] \[ \rightarrow \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 0 & -4 & 5 & -6 \\ 0 & 0 & 0 & 0 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 0 & 1 & -\frac{5}{4} & \frac{3}{2} \\ 0 & 0 & 0 & 0 \end{array}\right) \]\( z = \alpha \) (free)
\( y = \frac{3}{2} + \frac{5}{4}\alpha \)
\( x = 2 - y + z = 2 - \frac{3}{2} - \frac{5}{4}\alpha + \alpha \)
\[ \begin{gathered} = \frac{1}{2} - \frac{1}{4}\alpha \\[0.5em] \begin{pmatrix} x \\ y \\ z \end{pmatrix} = \begin{pmatrix} \frac{1}{2} - \frac{1}{4}\alpha \\ \frac{3}{2} + \frac{5}{4}\alpha \\ \alpha \end{pmatrix} = \begin{pmatrix} \frac{1}{2} \\ \frac{3}{2} \\ 0 \end{pmatrix} + \alpha \begin{pmatrix} -\frac{1}{4} \\ \frac{5}{4} \\ 1 \end{pmatrix} \end{gathered} \]Figure 12
3 planes intersect at a line.
Ex10
\[ \begin{cases} x + y - z = 2 \\ 2x - y + 3z = 1 \\ x - 2y + 4z = 0 \end{cases} \] \[ \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 2 & -1 & 3 & 1 \\ 1 & -2 & 4 & 0 \end{array}\right) \rightarrow \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 0 & -3 & 5 & -3 \\ 0 & -3 & 5 & -2 \end{array}\right) \] \[ \rightarrow \left(\begin{array}{ccc|c} 1 & 1 & -1 & 2 \\ 0 & -3 & 5 & -3 \\ 0 & 0 & 0 & 1 \end{array}\right) \]← no solutions.
Figure 13
3 parallel lines
3 planes forming 3 parallel lines with no common intersection.