Fall 2016, problem 30
Let $ d(n)$ be the number of positive divisors of the natural number $ n$ (this includes $1$). Find all $ n$ such that $ \frac {n} {d(n)}=p$ where $ p$ is a prime number.
Let $ d(n)$ be the number of positive divisors of the natural number $ n$ (this includes $1$). Find all $ n$ such that $ \frac {n} {d(n)}=p$ where $ p$ is a prime number.